Oprea

Multiple_Of_3_or_5

---

/*If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of
these multiples is 23.

Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.

Note: If the number is a multiple of both 3 and 5, only count it once.
*/

 

int solution(int number)
{
int sum =0;
for (int i = 0 ;i < number ; i++)
{
if((i%3 ==0) || (i%5==0))
sum+= i;
}
return sum;
}